project-euler-cpp/problem 6 at master · bashareid/project-euler-cpp · GitHub

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/*The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
*/
#include <iostream>
#include<cmath>
using namespace std;
int main() {
  int sum = 0,equal = 1, g, h, sum2 = 0;

  for(int i = 1; i <= 100; i++){
    sum=sum+i;
  }
  g = pow(sum, 2);
  cout<< g <<endl;

  for(int k = 1; k <= 100; k++){
     h = pow(k, 2);
     sum2 = sum2 + h;
    }
  cout<< sum2 <<endl;


  cout<< g - sum2 <<endl;


    return 0;

}