problem 38

"""
Take the number 192 and multiply it by each of 1, 2, and 3:

192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1
"""
perfect_pandigital = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
def check_pandigital(i, bigest_result):
  result = str(i * 1)
  if i < 10000:
    for j in  range(2, 3):
      result += str(i * j)
    temp = result  
    result = sorted(result)
    if result == perfect_pandigital:
      print(i , temp)

       
  
bigest_result  = []
for i in  range(1, 10000):
  check_pandigital(i, bigest_result)
#print(bigest_result)