problem 43

"""
The number, 1406357289, is a 0 to 9 pandigital number because it is made up of each of the digits 0 to 9 in some order, but it also has a rather interesting sub-string divisibility property.

Let d1 be the 1st digit, d2 be the 2nd digit, and so on. In this way, we note the following:

d2d3d4=406 is divisible by 2
d3d4d5=063 is divisible by 3
d4d5d6=635 is divisible by 5
d5d6d7=357 is divisible by 7
d6d7d8=572 is divisible by 11
d7d8d9=728 is divisible by 13
d8d9d10=289 is divisible by 17
Find the sum of all 0 to 9 pandigital numbers with this property.
"""
from itertools import permutations


p = permutations('0123456789')

solution = 0

for digits in p:
    if (int(''.join(digits[7:10])) % 17 == 0
     and
        int(''.join(digits[6:9])) % 13 == 0
         and
        int(''.join(digits[5:8])) % 11 == 0 
        and
        int(''.join(digits[4:7])) % 7 == 0 
        and
        int(''.join(digits[3:6])) % 5 == 0
         and
        int(''.join(digits[2:5])) % 3 == 0
         and
        int(''.join(digits[1:4])) % 2 == 0):

        solution += int(''.join(digits))

print(solution)